Match the items in Column-$I$ with relevant items in Column-$II$.
Column-$I$ Column-$II$ $A$. Positively charged ion $1$. $+7$ $B$. Oxidation number of all neutral atoms $2$. $-1$ $C$. Oxidation number of hydrogen $(H^+)$ $3$. $+1$ $D$. Oxidation number of fluorine in $NaF$ $4$. $0$ $E$. Negatively charged ion $5$. Cation $6$. Anion
| Column-$I$ | Column-$II$ |
|---|---|
| $A$. Positively charged ion | $1$. $+7$ |
| $B$. Oxidation number of all neutral atoms | $2$. $-1$ |
| $C$. Oxidation number of hydrogen $(H^+)$ | $3$. $+1$ |
| $D$. Oxidation number of fluorine in $NaF$ | $4$. $0$ |
| $E$. Negatively charged ion | $5$. Cation |
| $6$. Anion |
(A-5, B-4, C-3, D-2, E-6) The correct matches are:
$A-5$ (Positively charged ion is a Cation)
$B-4$ (Oxidation number of all neutral atoms is $0$)
$C-3$ (Oxidation number of $H^+$ is $+1$)
$D-2$ (Oxidation number of $F$ in $NaF$ is $-1$)
$E-6$ (Negatively charged ion is an Anion)
Thus,the correct sequence is: $A-5, B-4, C-3, D-2, E-6$.
$A-5$ (Positively charged ion is a Cation)
$B-4$ (Oxidation number of all neutral atoms is $0$)
$C-3$ (Oxidation number of $H^+$ is $+1$)
$D-2$ (Oxidation number of $F$ in $NaF$ is $-1$)
$E-6$ (Negatively charged ion is an Anion)
Thus,the correct sequence is: $A-5, B-4, C-3, D-2, E-6$.
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