The correct option for the above reaction is

Consider the following reaction,where:
$(A)$ The change in the functional group and
$(B)$ The corresponding change in the hybridization from the starting material to the final product are:
$CH_3-C \equiv N \xrightarrow[(ii) \ HI + \text{Red } P]{(i) \ SnCl_2, HCl / H_3O^{+}}$

What is $X$ in the following reaction?
$2 CH_3COCH_3 \stackrel{Ba(OH)_2}{\longrightarrow} X$

$CH_3COOH$ $\xrightarrow{LiAlH_4} X$ $\xrightarrow{Cu, 300^{\circ}C} Y$ $\xrightarrow{\text{Dilute } NaOH} Z$. In the above reaction,$Z$ is:

Product $(B)$ is :

Given below are two statements,one is labelled as Assertion $A$ and the other is labelled as Reason $R$.
Assertion $A$: $3$-chloro-$2$-methylpentan-$3$-one can be subjected to Wolff-Kishner reduction to give $3$-chloro-$2$-methylpentane.
Reason $R$: Wolff-Kishner reduction is used to convert $C=O$ into $CH_2$.