Given below are two statements,one is labelle | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Assertion $A$ is false. Wolff-Kishner reduction involves the use of a strong base (like $KOH$ or $EtO^-K^+$) at high temperatures. The substrate $

Vedclass · Accepted Answer

$A$ is false but $R$ is true.

Vedclass · Answer

(C) Assertion $A$ is false. Wolff-Kishner reduction involves the use of a strong base (like $KOH$ or $EtO^-K^+$) at high temperatures. The substrate $3$-chloro-$2$-methylpentan-$3$-one contains a chlorine atom at the $\alpha$-position relative to the carbonyl group. In the presence of a strong base,this compound undergoes dehydrohalogenation (elimination of $HCl$) to form an $\alpha,\beta$-unsaturated ketone rather than the desired reduction product.Reason $R$ is true. Wolff-Kishner reduction is indeed a standard method used to reduce carbonyl groups $(C=O)$ to methylene groups $(CH_2)$.

Similar Questions

What is meant by the following terms? Give an example of the reaction in each case.
$(i)$ Cyanohydrin
$(ii)$ Acetal
$(iii)$ Semicarbazone
$(iv)$ Aldol
$(v)$ Hemiacetal
$(vi)$ Oxime
$(vii)$ Ketal
$(viii)$ Imine
$(ix)$ $2,4-DNP$ derivative
$(x)$ Schiff's base

For making a distinction between $2$-pentanone and $3$-pentanone,the reagent to be employed is

Write the reduction reaction of aldehydes and ketones.

Identify the product $Y$ in the following reaction sequence:
$CH_3CHO + CH_3MgI$ $\xrightarrow{\quad} X$ $\xrightarrow{H_2O/H^+} Y$

Reductive amination of $A$ forms :
$A$ :

Vedclass Test Series

Exam Paper Generator

Online Exam Module