The circuit shown contains a 12 , V battery,a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) In the given circuit,the battery provides a potential difference of $12 \, V$. Diode $D_1$ is connected in reverse bias relative to the positive t

Vedclass · Accepted Answer

$2$

Vedclass · Answer

(B) In the given circuit,the battery provides a potential difference of $12 \, V$. Diode $D_1$ is connected in reverse bias relative to the positive terminal of the battery,so it acts as an open circuit (no current flows through the $3 \, \Omega$ branch). Diode $D_2$ is connected in forward bias,so it acts as a short circuit (ideal diode). Therefore,the total resistance of the circuit is the sum of the $4 \, \Omega$ resistor and the $2 \, \Omega$ resistor in the active branch: $R_{eq} = 4 \, \Omega + 2 \, \Omega = 6 \, \Omega$. Using Ohm's law,the current $I$ is given by $I = \frac{V}{R_{eq}} = \frac{12 \, V}{6 \, \Omega} = 2 \, A$.

Similar Questions

For the circuit shown in the figure,the equivalent resistance between points $A$ and $B$ for two cases $(i)$ $V_A > V_B$ and (ii) $V_B > V_A$ is $\qquad \Omega$ and $\qquad \Omega$ respectively. ($D_1$ and $D_2$ are ideal diodes)

The $V-I$ characteristic of a diode is shown in the figure. The ratio of forward to reverse bias resistance is

The potential barrier of a $P-N$ junction is $0.5 \ V$. The thickness of the depletion layer is $5.0 \times 10^{-7} \ m$. Calculate the electric field.

In order to forward bias a $PN$ junction,the negative terminal of the battery is connected to

When a reverse bias is applied to a $p-n$ junction diode,what happens to the potential barrier?

Vedclass Test Series

Exam Paper Generator

Online Exam Module