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Question

(B) Time taken to cover the first $100 \, km = \frac{100}{30} = \frac{10}{3} \, h$.Time taken to cover the second $100 \, km = \frac{100}{40} = \frac{

Vedclass · Accepted Answer

$38.3$

Vedclass · Answer

(B) Time taken to cover the first $100 \, km = \frac{100}{30} = \frac{10}{3} \, h$.Time taken to cover the second $100 \, km = \frac{100}{40} = \frac{5}{2} \, h$.Time taken to cover the last $100 \, km = \frac{100}{50} = 2 \, h$.Total time taken $= \frac{10}{3} + \frac{5}{2} + 2 = \frac{20 + 15 + 12}{6} = \frac{47}{6} \, h$.Total distance covered $= 100 + 100 + 100 = 300 \, km$.Average speed $= \frac{	ext{Total distance}}{	ext{Total time}} = \frac{300}{47/6} = \frac{300 	imes 6}{47} = \frac{1800}{47} \approx 38.3 \, km/h$.

The average speed of a train running at a speed of $30 \, km/h$ during the first $100 \, km$,at $40 \, km/h$ during the second $100 \, km$,and at $50 \, km/h$ during the last $100 \, km$ is nearly (in $km/h$):

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