The correct order of bond dissociation energy | vedclass

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Question

The bond order of $N_2,$ $O_2,$ and $O_2^-$ are respectively $3,2$ and $1.5$

Since higher bond order implies higher bond dissociation energy hence

Vedclass · Accepted Answer

$N_2 > O_2 > O_2^-$

Vedclass · Answer

The bond order of $N_2,$ $O_2,$ and $O_2^-$ are respectively $3,2$ and $1.5$

Since higher bond order implies higher bond dissociation energy hence the correct orde will be 

$N_2 > O_2 > O_2^-$

The correct order of bond dissociation energy among $N_2, O_2, O_2^-$ is shown in which of the following arrangements?

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