The area of a quadrilateral is 420 , m^{2} an | vedclass

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(C) The area of a quadrilateral can be calculated using the formula: $	ext{Area} = \frac{1}{2} 	imes d 	imes (p_{1} + p_{2})$,where $d$ is the leng

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$28$

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(C) The area of a quadrilateral can be calculated using the formula: $	ext{Area} = \frac{1}{2} 	imes d 	imes (p_{1} + p_{2})$,where $d$ is the length of the diagonal and $p_{1}, p_{2}$ are the lengths of the perpendiculars from the opposite vertices to the diagonal.Given: $	ext{Area} = 420 \, m^{2}$,$p_{1} = 18 \, m$,and $p_{2} = 12 \, m$.Substituting the values into the formula:$420 = \frac{1}{2} 	imes d 	imes (18 + 12)$$420 = \frac{1}{2} 	imes d 	imes 30$$420 = 15 	imes d$$d = \frac{420}{15}$$d = 28 \, m$.Thus,the length of the diagonal is $28 \, m$.

The area of a quadrilateral is $420 \, m^{2}$ and the perpendiculars drawn to one diagonal from the opposite vertices are $18 \, m$ and $12 \, m$. Then,the length of the diagonal is......$m$

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