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(D) The amplitude of the magnetic field of an electromagnetic wave in a vacuum is given as $B_0 = 510 \; nT = 510 	imes 10^{-9} \; T$.The speed of li

Vedclass · Accepted Answer

$153$

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(D) The amplitude of the magnetic field of an electromagnetic wave in a vacuum is given as $B_0 = 510 \; nT = 510 	imes 10^{-9} \; T$.The speed of light in a vacuum is $c = 3 	imes 10^8 \; m/s$.The amplitude of the electric field $(E_0)$ of an electromagnetic wave is related to the amplitude of the magnetic field $(B_0)$ by the relation $E_0 = c B_0$.Substituting the given values:$E_0 = (3 	imes 10^8 \; m/s) 	imes (510 	imes 10^{-9} \; T)$$E_0 = 3 	imes 510 	imes 10^{-1} \; N/C$$E_0 = 1530 	imes 10^{-1} \; N/C = 153 \; N/C$.Therefore,the amplitude of the electric field part of the wave is $153 \; N/C$.

The amplitude of the magnetic field part of a harmonic electromagnetic wave in vacuum is $B_0 = 510 \; nT$. What is the amplitude of the electric field (in $N/C$) part of the wave?

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