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(B) The relationship between the speed of light $(c)$,frequency $(v)$,and wavelength $(\lambda)$ is given by the formula: $c = v \lambda$.Given that t

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$3660$

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(B) The relationship between the speed of light $(c)$,frequency $(v)$,and wavelength $(\lambda)$ is given by the formula: $c = v \lambda$.Given that the speed of light $c = 3 	imes 10^{8} \ m/s$ and the frequency $v = 8.196 	imes 10^{6} \ Hz$.Rearranging the formula to solve for wavelength: $\lambda = \frac{c}{v}$.Substituting the values: $\lambda = \frac{3 	imes 10^{8}}{8.196 	imes 10^{6}}$.$\lambda = \frac{3}{8.196} 	imes 10^{2} \ m$.$\lambda \approx 0.3660 	imes 10^{2} \ m$.$\lambda = 36.60 \ m$.Converting meters to centimeters: $36.60 \ m = 3660 \ cm$.Therefore,the correct option is $B$.

If a source is transmitting electromagnetic waves of frequency $8.196 \times 10^{6} \ Hz$,then the wavelength of the $EM$ waves transmitted from the source will be . . . . . . . (in $cm$)

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