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(C) The energy density $u$ of an electromagnetic wave is given by $u = \frac{1}{2} \epsilon_0 E^2 + \frac{1}{2\mu_0} B^2$. Since the electric field $E

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$8 	imes 10^{14} \,Hz$

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(C) The energy density $u$ of an electromagnetic wave is given by $u = \frac{1}{2} \epsilon_0 E^2 + \frac{1}{2\mu_0} B^2$. Since the electric field $E$ and magnetic field $B$ oscillate as $E = E_0 \sin(\omega t)$ and $B = B_0 \sin(\omega t)$, the energy density involves terms like $\sin^2(\omega t)$. Using the trigonometric identity $\sin^2(\omega t) = \frac{1 - \cos(2\omega t)}{2}$, we see that the energy density oscillates with an angular frequency of $2\omega$. Therefore, the frequency of energy oscillation is $f_{energy} = 2f = 2 	imes (4 	imes 10^{14} \,Hz) = 8 	imes 10^{14} \,Hz$.

An electromagnetic wave having frequency $4 \times 10^{14} \,Hz$ is passing through a small volume. The energy contained in this volume oscillates with frequency

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