The amplification factor of a triode is 20. I | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The amplification factor $\mu$ of a triode is defined as the ratio of the change in plate voltage to the change in grid voltage for a constant pla

Vedclass · Accepted Answer

$4$

Vedclass · Answer

(B) The amplification factor $\mu$ of a triode is defined as the ratio of the change in plate voltage to the change in grid voltage for a constant plate current: $\mu = -\frac{\Delta V_p}{\Delta V_G}$.Given: $\mu = 20$ and $\Delta V_G = -0.2\, V$ (since the potential is reduced).To keep the plate current constant,we rearrange the formula: $\Delta V_p = -\mu 	imes \Delta V_G$.Substituting the values: $\Delta V_p = -20 	imes (-0.2\, V) = 4\, V$.Therefore,the plate voltage must be increased by $4\, V$.

The amplification factor of a triode is $20$. If the grid potential is reduced by $0.2\, V$,then to keep the plate current constant,its plate voltage must be increased by how many volts?

Similar Questions

The plate resistance of a triode is $2.5 \times 10^{4} \ \Omega$ and mutual conductance is $2 \times 10^{-3} \ \text{mho}$. What will be the value of the amplification factor?

The amplification factor of a triode valve is $15$. If the grid voltage is changed by $0.3 \,V$,what is the change in plate voltage required to keep the plate current constant (in $V$)?

In a diode,when there is a saturation current,the plate resistance will be

For a given plate-voltage,the plate current in a triode is maximum when the potential of

When the plate voltage in a diode valve is increased from $100 \, V$ to $150 \, V$, the plate current increases from $7.5 \, mA$ to $12 \, mA$. The dynamic plate resistance will be.... $k \, \Omega$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module