For a given plate-voltage,the plate current in a triode is maximum when the potential of

  • A
    The grid is positive and plate is negative
  • B
    The grid is positive and plate is positive
  • C
    The grid is zero and plate is positive
  • D
    The grid is negative and plate is positive

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Similar Questions

The linear portions of the characteristic curves of a triode valve give the following readings. The plate resistance is ....... $\Omega$.
$V_g$ (volt)$0$$-2$$-4$$-6$
$I_p$ (mA) for $V_p = 150$ $V$$15$$12.5$$10$$7.5$
$I_p$ (mA) for $V_p = 120$ $V$$10$$7.5$$5$$2.5$

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The plate resistance of two triode valves is $2 \, k\Omega$ and $4 \, k\Omega$. The amplification factor of each valve is $40$. The ratio of voltage amplification,when used with a $4 \, k\Omega$ load resistance,will be:

For a given triode,$\mu = 20$. The load resistance is $1.5$ times the anode resistance. The voltage gain will be:

The mutual characteristic curves of a triode are as shown in the figure. The cut-off voltage for the triode is.....$V$.

If ${R_p} = 7 \text{ k}\Omega$ and ${g_m} = 2.5 \text{ millimho}$, then on increasing the plate voltage by $50 \text{ V}$, how much must the grid voltage be changed so that the plate current remains the same? (in $V$)

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