The plate resistance of a triode is 2.5 times | vedclass

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(A) The amplification factor $(\mu)$ of a triode is defined as the product of plate resistance $(r_p)$ and mutual conductance $(g_m)$.Given:Plate resi

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$50$

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(A) The amplification factor $(\mu)$ of a triode is defined as the product of plate resistance $(r_p)$ and mutual conductance $(g_m)$.Given:Plate resistance $(r_p)$ = $2.5 	imes 10^{4} \ \Omega$Mutual conductance $(g_m)$ = $2 	imes 10^{-3} \ 	ext{mho}$Formula:$\mu = r_p 	imes g_m$Calculation:$\mu = (2.5 	imes 10^{4}) 	imes (2 	imes 10^{-3})$$\mu = 5.0 	imes 10^{1} = 50$Therefore,the amplification factor is $50$.

The plate resistance of a triode is $2.5 \times 10^{4} \ \Omega$ and mutual conductance is $2 \times 10^{-3} \ \text{mho}$. What will be the value of the amplification factor?

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