(A) In vessel $A$,the fraction of acid is $\frac{4}{7}$.In vessel $B$,the fraction of acid is $\frac{2}{5}$.The target mixture in vessel $C$ should ha

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(A) In vessel $A$,the fraction of acid is $\frac{4}{7}$.In vessel $B$,the fraction of acid is $\frac{2}{5}$.The target mixture in vessel $C$ should have half acid,so the fraction is $\frac{1}{2}$.Using the rule of alligation:Ratio of vessel $A$ to vessel $B = (\frac{1}{2} - \frac{2}{5}) : (\frac{4}{7} - \frac{1}{2})$$= (\frac{5-4}{10}) : (\frac{8-7}{14})$$= \frac{1}{10} : \frac{1}{14}$$= 14 : 10$$= 7 : 5$Thus,the required ratio is $7:5$.

Competitive Quantitative Aptitude Mixture and Alligation Mixture and Alligation

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The acid and water in two vessels $A$ and $B$ are in the ratio $4:3$ and $2:3$. In what ratio should the liquids in both the vessels be mixed to obtain a new mixture in vessel $C$ containing half acid and half water?

A
$7:5$
B
$5:7$
C
$7:3$
D
$5:3$

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Mixture and Alligation

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Mixture and Alligation

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The acid and water in two vessels $A$ and $B$ are in the ratio $4:3$ and $2:3$. In what ratio should the liquids in both the vessels be mixed to obtain a new mixture in vessel $C$ containing half acid and half water?

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