The ratio of the quantities of an acid and wa | vedclass

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(D) Let the quantity of acid in the original mixture be $x$ litres and the quantity of water be $3x$ litres.According to the problem,when $5$ litres o

Vedclass · Accepted Answer

$45$

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(D) Let the quantity of acid in the original mixture be $x$ litres and the quantity of water be $3x$ litres.According to the problem,when $5$ litres of acid is added,the new ratio of acid to water becomes $1:2$.So,$\frac{x+5}{3x} = \frac{1}{2}$.Cross-multiplying,we get $2(x+5) = 3x$.$2x + 10 = 3x$.$3x - 2x = 10$,which gives $x = 10$.The original quantity of the mixture was $x + 3x = 4x = 4(10) = 40$ litres.After adding $5$ litres of acid,the quantity of the new mixture is $40 + 5 = 45$ litres.

The ratio of the quantities of an acid and water in a mixture is $1:3$. If $5$ $litres$ of acid is further added to the mixture,the new ratio becomes $1:2$. The quantity of the new mixture in litres is

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