The acceleration due to gravity on the planet $ A $ is $9$ times the acceleration due to gravity on planet $B$. $A$ man jumps to a height of $2\,m$ on the surface of $ A$. What is the height of jump by the same person on the planet $B$..........$m$

The mass and diameter of a planet have twice the value of the corresponding parameters of earth. Acceleration due to gravity on the surface of the planet is ........ $m/{\sec ^2}$.

Assuming the earth to be a sphere of uniform mass density, a body weighed $300 \mathrm{~N}$ on the surface of earth. How much it would weigh at $R / 4$ depth under surface of earth?

If $M$ the mass of the earth and $R$ its radius, the ratio of the gravitational acceleration and the gravitational constant is

If the density of the earth is doubled keeping its radius constant then acceleration due to gravity will be........ $m/{s^2}$ . $(g = 9.8\,m/{s^2})$

Given below are two statements: One is labelled as Assertion $A$ and the other is labelled as Reason $R$.

Assertion $A$: If we move from poles to equator, the direction of acceleration due to gravity of earth always points towards the center of earth without any variation in its magnitude.

Reason $R $: At equator, the direction of acceleration due to the gravity is towards the center of earth. In the light of above statements, choose the correct answer from the options given below