If $M$ the mass of the earth and $R$ its radius, the ratio of the gravitational acceleration and the gravitational constant is
$\frac{{{R^2}}}{M}$
$\frac{M}{{{R^2}}}$
$M{R^2}$
$\frac{M}{R}$
Assuming the earth to be a sphere of uniform density, the acceleration due to gravity inside the earth at a distance of $r$ from the centre is proportional to
If the change in the value of $‘g’$ at a height $h$ above the surface of the earth is the same as at a depth $x$ below it, then (both $x$ and $h$ being much smaller than the radius of the earth)
A man can jump to a height of $1.5 \,m$ on a planet $A$. What is the height he may be able to jump on another planet whose density and radius are, respectively, one-quarter and one-third that of planet $A$ ....... $m$
Consider two spherical planets of same average density. Second planet is $8$ times as massive as first planet. The ratio of the acceleration due to gravity of the second planet to that of the first planet is
If the earth were to cease rotating about its own axis. The increase in the value of $g$ in $C.G.S.$ system at a place of latitude of $45^o$ will be ........ $cm/sec^{2}$.