The abscissa of the point of intersection of the less than type and of the more than type cumulative frequency curves of a grouped data gives its
- Amean
- Bmode
- Cmedian
- Dall the three above
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Similar Questions
Calculate the mean of the following frequency distribution:
Class $80-90$ $90-100$ $100-110$ $110-120$ $120-130$ $130-140$ $140-150$ $150-160$ $160-170$ Frequency $6$ $18$ $78$ $80$ $100$ $72$ $0$ $40$ $6$
(in $.55$)
| Class | $80-90$ | $90-100$ | $100-110$ | $110-120$ | $120-130$ | $130-140$ | $140-150$ | $150-160$ | $160-170$ |
|---|---|---|---|---|---|---|---|---|---|
| Frequency | $6$ | $18$ | $78$ | $80$ | $100$ | $72$ | $0$ | $40$ | $6$ |
Medium
View SolutionFor some given data,if $Z = 95$ and $\bar{x} = 98,$ then $M = \ldots \ldots \ldots$
Easy
View SolutionIf $Z - M = 4$,then $M - \bar{x} = \dots$
Medium
View SolutionThe median of the following frequency distribution is $525$ and the total frequency is $100$. Find the missing frequencies $x$ and $y$.
Class $0-100$ $100-200$ $200-300$ $300-400$ $400-500$ $500-600$ $600-700$ $700-800$ $800-900$ $900-1000$ Frequency $2$ $5$ $x$ $12$ $17$ $20$ $y$ $9$ $7$ $4$
| Class | $0-100$ | $100-200$ | $200-300$ | $300-400$ | $400-500$ | $500-600$ | $600-700$ | $700-800$ | $800-900$ | $900-1000$ |
| Frequency | $2$ | $5$ | $x$ | $12$ | $17$ | $20$ | $y$ | $9$ | $7$ | $4$ |
Difficult
View SolutionIn the formula $M = l + \frac{(\frac{n}{2} - cf)}{f} \times h$ for the median,$n = \ldots \ldots \ldots$
Easy
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