Calculate the mean of the following frequency | vedclass

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(D) To calculate the mean,we use the formula $\bar{x} = \frac{\sum f_i x_i}{\sum f_i}$,where $x_i$ is the class mark.$1$. Calculate class marks $(x_i)

Vedclass · Accepted Answer

$122$

Vedclass · Answer

(D) To calculate the mean,we use the formula $\bar{x} = \frac{\sum f_i x_i}{\sum f_i}$,where $x_i$ is the class mark.$1$. Calculate class marks $(x_i)$: $85, 95, 105, 115, 125, 135, 145, 155, 165$.$2$. Calculate $f_i x_i$:$6 	imes 85 = 510$$18 	imes 95 = 1710$$78 	imes 105 = 8190$$80 	imes 115 = 9200$$100 	imes 125 = 12500$$72 	imes 135 = 9720$$0 	imes 145 = 0$$40 	imes 155 = 6200$$6 	imes 165 = 990$$3$. Sum of frequencies $\sum f_i = 6 + 18 + 78 + 80 + 100 + 72 + 0 + 40 + 6 = 400$.$4$. Sum of products $\sum f_i x_i = 510 + 1710 + 8190 + 9200 + 12500 + 9720 + 0 + 6200 + 990 = 49020$.$5$. Mean $\bar{x} = \frac{49020}{400} = 122.55$.

Class	$30-40$	$40-50$	$50-60$	$60-70$	$70-80$
Frequency	$3$	$x$	$7$	$7$	$y$

Marks	$30-35$	$35-40$	$40-45$	$45-50$	$50-55$	$55-60$	$60-65$
Frequency	$14$	$16$	$18$	$23$	$18$	$8$	$3$

Calculate the mean of the following frequency distribution:

Class $80-90$ $90-100$ $100-110$ $110-120$ $120-130$ $130-140$ $140-150$ $150-160$ $160-170$

Frequency $6$ $18$ $78$ $80$ $100$ $72$ $0$ $40$ $6$
(in $.55$)

Similar Questions

The mean of the following data is $55.5$ and the total frequency is $20$. Find the missing frequencies $x$ and $y$.
Class $30-40$ $40-50$ $50-60$ $60-70$ $70-80$
Frequency $3$ $x$ $7$ $7$ $y$

The percentage of marks obtained by $100$ students in an examination are given below:

Marks $30-35$ $35-40$ $40-45$ $45-50$ $50-55$ $55-60$ $60-65$

Frequency $14$ $16$ $18$ $23$ $18$ $8$ $3$

Determine the median percentage of marks.

If $3 \bar{x} = 2 M = 60,$ then $Z = \dots$

In the formula $\bar{x} = A + \frac{\Sigma f_{i} d_{i}}{\Sigma f_{i}}$ for the mean,$d_{i} = \dots$

For a given frequency distribution,$A = 200$,$\Sigma f_{i} = 45$,$\Sigma f_{i} u_{i} = -216$ and $c = 10$. Then,mean $\bar{x} = \dots$

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Calculate the mean of the following frequency distribution: Class $80-90$ $90-100$ $100-110$ $110-120$ $120-130$ $130-140$ $140-150$ $150-160$ $160-170$ Frequency $6$ $18$ $78$ $80$ $100$ $72$ $0$ $40$ $6$ (in $.55$)