The mathrm{E}^{circ} value for the mathrm{Mn} | vedclass

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Question

$\mathrm{E}_{\mathrm{Mn}^{3+} / \mathrm{Mn}^{2+}}^0>\mathrm{E}_{\mathrm{Cr}^{3+} / \mathrm{Cr}^{2+}}^0 	ext { or } \mathrm{E}_{\mathrm{Fe}^{3+} /

Vedclass · Accepted Answer

$d^4$ to $d^5$ configuration

Vedclass · Answer

$\mathrm{E}_{\mathrm{Mn}^{3+} / \mathrm{Mn}^{2+}}^0>\mathrm{E}_{\mathrm{Cr}^{3+} / \mathrm{Cr}^{2+}}^0 	ext { or } \mathrm{E}_{\mathrm{Fe}^{3+} / \mathrm{Fe}^{2+}}^0$

Electronic configuration of $\mathrm{Mn}^{3+}=[\mathrm{Ar}] 3 d^4$

Electronic configuration of $\mathrm{Mn}^{2+}=[\mathrm{Ar}] 3 d^5$

Electronic configuration of $\mathrm{Cr}^{3+}=[\mathrm{Ar}] 3 d^\beta$

Electronic configuration of $\mathrm{Cr}^{2+}=[\mathrm{Ar}] 3 d^4$

As $\mathrm{Mn}^{3+}$ from $d^4$ configuration goes to more stable $d^5$ configuration (Half filled), due to more exchange energy in $d^5$ configuration.

The $\mathrm{E}^{\circ}$ value for the $\mathrm{Mn}^{3 } / \mathrm{Mn}^{2+}$ couple is more positive than that of $\mathrm{Cr}^{3+} / \mathrm{Cr}^{2+}$ or $\mathrm{Fe}^{3+} / \mathrm{Fe}^{2 }$ due to change of

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The $\mathrm{E}^{\circ}$ value for the $\mathrm{Mn}^{3 *} / \mathrm{Mn}^{2+}$ couple is more positive than that of $\mathrm{Cr}^{3+} / \mathrm{Cr}^{2+}$ or $\mathrm{Fe}^{3+} / \mathrm{Fe}^{2 *}$ due to change of