The mathrm{E}^{circ} value for the mathrm{Mn} | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

$\mathrm{E}_{\mathrm{Mn}^{3+} / \mathrm{Mn}^{2+}}^0>\mathrm{E}_{\mathrm{Cr}^{3+} / \mathrm{Cr}^{2+}}^0 	ext { or } \mathrm{E}_{\mathrm{Fe}^{3+} /

Vedclass · Accepted Answer

$d^4$ to $d^5$ configuration

Vedclass · Answer

$\mathrm{E}_{\mathrm{Mn}^{3+} / \mathrm{Mn}^{2+}}^0>\mathrm{E}_{\mathrm{Cr}^{3+} / \mathrm{Cr}^{2+}}^0 	ext { or } \mathrm{E}_{\mathrm{Fe}^{3+} / \mathrm{Fe}^{2+}}^0$

Electronic configuration of $\mathrm{Mn}^{3+}=[\mathrm{Ar}] 3 d^4$

Electronic configuration of $\mathrm{Mn}^{2+}=[\mathrm{Ar}] 3 d^5$

Electronic configuration of $\mathrm{Cr}^{3+}=[\mathrm{Ar}] 3 d^\beta$

Electronic configuration of $\mathrm{Cr}^{2+}=[\mathrm{Ar}] 3 d^4$

As $\mathrm{Mn}^{3+}$ from $d^4$ configuration goes to more stable $d^5$ configuration (Half filled), due to more exchange energy in $d^5$ configuration.

The $\mathrm{E}^{\circ}$ value for the $\mathrm{Mn}^{3 } / \mathrm{Mn}^{2+}$ couple is more positive than that of $\mathrm{Cr}^{3+} / \mathrm{Cr}^{2+}$ or $\mathrm{Fe}^{3+} / \mathrm{Fe}^{2 }$ due to change of

Similar Questions

Which of the following compounds show colour due to $d-d$ transition?

Which of the following does not contain copper

Write a note on oxides and oxoanions of transition elements.

German silver is an alloy of $Cu$ with

Chloro compound of Vanadium has only spin magnetic moment of $1.73\, BM$. This Vanadium chloride has the formula

The $\mathrm{E}^{\circ}$ value for the $\mathrm{Mn}^{3 *} / \mathrm{Mn}^{2+}$ couple is more positive than that of $\mathrm{Cr}^{3+} / \mathrm{Cr}^{2+}$ or $\mathrm{Fe}^{3+} / \mathrm{Fe}^{2 *}$ due to change of