The 9^{th} term of the sequence 0, 3, 8, 15, | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The given sequence is $0, 3, 8, 15, 24, 35, \dots$Observe the differences between consecutive terms:$3 - 0 = 3$$8 - 3 = 5$$15 - 8 = 7$$24 - 15 = 9

Vedclass · Accepted Answer

$80$

Vedclass · Answer

(C) The given sequence is $0, 3, 8, 15, 24, 35, \dots$Observe the differences between consecutive terms:$3 - 0 = 3$$8 - 3 = 5$$15 - 8 = 7$$24 - 15 = 9$$35 - 24 = 11$The differences are consecutive odd numbers: $3, 5, 7, 9, 11, \dots$To find the $9^{th}$ term,we continue the pattern:$7^{th}$ term $= 35 + 13 = 48$$8^{th}$ term $= 48 + 15 = 63$$9^{th}$ term $= 63 + 17 = 80$Alternatively,the $n^{th}$ term of the sequence is given by $a_n = n^2 - 1$.For $n = 9$,$a_9 = 9^2 - 1 = 81 - 1 = 80$.

The $9^{th}$ term of the sequence $0, 3, 8, 15, 24, 35, \dots$ is

Similar Questions

If $m$ arithmetic means $(A.Ms)$ and three geometric means $(G.Ms)$ are inserted between $3$ and $243$ such that the $4^{\text{th}}$ $A.M.$ is equal to the $2^{\text{nd}}$ $G.M.$,then $m$ is equal to:

If $\alpha, \beta, \gamma$ are the geometric means between $ca, ab$; $ab, bc$; and $bc, ca$ respectively,where $a, b, c$ are in $A.P.$,then $\alpha^2, \beta^2, \gamma^2$ are in

The number $111...1$ ($91$ times) is a:

Write the seventh term of the following $GP$: $39366, 13122, 4374, 1458, \ldots$

The sum $11^{2} + 12^{2} + \cdots + 20^{2} + 21^{2} = ?$

Vedclass Test Series

Exam Paper Generator

Online Exam Module