Write the seventh term of the following GP: 3 | vedclass

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(B) The given sequence is a Geometric Progression $(GP)$.First term $(a)$ = $39366$.Common ratio $(r)$ = $\frac{13122}{39366} = \frac{1}{3}$.The $n^{t

Vedclass · Accepted Answer

$54$

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(B) The given sequence is a Geometric Progression $(GP)$.First term $(a)$ = $39366$.Common ratio $(r)$ = $\frac{13122}{39366} = \frac{1}{3}$.The $n^{th}$ term of a $GP$ is given by the formula $a_n = a \cdot r^{n-1}$.To find the seventh term $(a_7)$,we substitute $n = 7$,$a = 39366$,and $r = \frac{1}{3}$:$a_7 = 39366 \cdot \left(\frac{1}{3}\right)^{7-1}$$a_7 = 39366 \cdot \left(\frac{1}{3}\right)^6$$a_7 = 39366 \cdot \frac{1}{729}$$a_7 = 54$.

Write the seventh term of the following $GP$: $39366, 13122, 4374, 1458, \ldots$

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