Surbhi bought a combined total of 25 i-pads a | vedclass

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(B) Let the number of i-pads be $x$ and i-phones be $y$. Given $x + y = 25$. Let $CP$ of an i-pad be $C_p$. Then $CP$ of an i-phone is $0.5 C_p$.Selli

Vedclass · Accepted Answer

Loss of $Rs. 48500$

Vedclass · Answer

(B) Let the number of i-pads be $x$ and i-phones be $y$. Given $x + y = 25$. Let $CP$ of an i-pad be $C_p$. Then $CP$ of an i-phone is $0.5 C_p$.Selling Price $(SP)$ of an i-pad $= 1.2 C_p$. Profit per i-pad $= 0.2 C_p$.Selling Price $(SP)$ of an i-phone $= 0.5 C_p + 2000$. Profit per i-phone $= 2000$.Total profit from $0.75x$ i-pads and $2$ i-phones is $49000$.$(0.75x)(0.2 C_p) + 2(2000) = 49000 \implies 0.15 x C_p = 45000 \implies x C_p = 300000$.Since $3$ i-phones were unsold,$y = 2 + 3 = 5$. Thus $x = 25 - 5 = 20$.$20 C_p = 300000 \implies C_p = 15000$. $CP$ of i-phone $= 7500$.Total Cost Price $= 20(15000) + 5(7500) = 300000 + 37500 = 337500$.Total Revenue $= (0.75 	imes 20)(1.2 	imes 15000) + 2(7500 + 2000) = 15(18000) + 2(9500) = 270000 + 19000 = 289000$.Overall Loss $= 337500 - 289000 = 48500$.

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