Nisha bought a number of oranges at 2 for a r | vedclass

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Question

Let she bought $60$ oranges of each type

$C.P.$ of type $1$ orange $=0.5 	imes 1 / 2$

Total cost price of type $1$ orange $=0.5 	imes 1 / 2

Vedclass · Accepted Answer

$6$

Vedclass · Answer

Let she bought $60$ oranges of each type

$C.P.$ of type $1$ orange $=0.5 	imes 1 / 2$

Total cost price of type $1$ orange $=0.5 	imes 1 / 2 	imes 60$

$=30$

Total $C.P.$ of type $2$ orange $=1 / 3 	imes 60=20$

$C.P.$ $=30+20=50$

Profit $=\frac{20}{100} 	imes 50=10$

Total $S.P.$ $50+10=60$

Now, this $S.P.$ is for $120$ oranges

For $12$ oranges, $S.P. =12 	imes \frac{60}{120}=6$

Nisha bought a number of oranges at $2$ for a rupee and an equal number at $3$ for a rupee. To make a profit of $20 \%$ she should sell a dozen for (in $Rs.$)

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