State whether the following is true or false. Justify your answer.
$\sin \theta = \cos \theta$ for all values of $\theta$.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(B) The statement $\sin \theta = \cos \theta$ for all values of $\theta$ is false.
Justification:
$1$. The equation $\sin \theta = \cos \theta$ holds true only when $\theta = 45^{\circ}$.
$2$. At $\theta = 45^{\circ}$,$\sin 45^{\circ} = \frac{1}{\sqrt{2}}$ and $\cos 45^{\circ} = \frac{1}{\sqrt{2}}$.
$3$. For other values of $\theta$,the statement is incorrect. For example,at $\theta = 30^{\circ}$,$\sin 30^{\circ} = \frac{1}{2}$ while $\cos 30^{\circ} = \frac{\sqrt{3}}{2}$.
$4$. Since $\frac{1}{2} \neq \frac{\sqrt{3}}{2}$,the statement is false.

Explore More

Similar Questions

Write all the other trigonometric ratios of $\angle A$ in terms of $\sec A$.

$\sin 2A = 2 \sin A$ is true when $A =$ (in $^{\circ}$)

Prove that $\frac{\sin \theta-\cos \theta+1}{\sin \theta+\cos \theta-1}=\frac{1}{\sec \theta-\tan \theta},$ using the identity $\sec ^{2} \theta=1+\tan ^{2} \theta.$

Difficult
View Solution

If $\tan (A + B) = \sqrt{3}$ and $\tan (A - B) = \frac{1}{\sqrt{3}}$,where $0^{\circ} < A + B \leq 90^{\circ}$ and $A > B$,find the values of $A$ and $B$.

$\frac{1+\tan ^{2} A}{1+\cot ^{2} A} = \dots$

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo