Standing waves are produced in a $10 \, m$ long stretched string fixed at both ends. If the string vibrates in $5$ segments and the wave velocity is $20 \, m/s$,the frequency is ....... $Hz$.

In a standing wave on a string $:-$

$A$ string of length $1\,m$ and linear mass density $0.01\,kg/m$ is stretched to a tension of $100\,N$. When both ends of the string are fixed,the three lowest frequencies for standing waves are $f_1, f_2$,and $f_3$. When only one end of the string is fixed,the three lowest frequencies for standing waves are $n_1, n_2$,and $n_3$. Then:

$A$ wave disturbance in a medium is described by $y(x, t) = 0.02 \cos(50 \pi t + \frac{\pi}{2}) \cos(10 \pi x)$,where $x$ and $y$ are in metres and $t$ is in seconds.

Give the distance between consecutive nodes and antinodes in terms of wavelength $\lambda$.

The equation of a wave disturbance is given as: $y = 0.02 \cos \left( \frac{\pi}{2} + 50\pi t \right) \cos (10 x),$ where $x$ and $y$ are in meters and $t$ is in seconds. Choose the wrong statement: