The square root of $0 . \overline{4}$ is

$\left(\frac{\sqrt{625}}{11} \times \frac{14}{\sqrt{25}} \times \frac{11}{\sqrt{196}}\right)$ is equal to

$A$ General wishing to draw up his $5180$ men in the form of a solid square found that he had $4$ men less. If he could get four more men and form the solid square,the number of men in the front row is

$\sqrt{6354} \times 34.993 = ?$

$\left[\frac{3 \sqrt{2}}{\sqrt{6}-\sqrt{3}}-\frac{4 \sqrt{3}}{\sqrt{6}-\sqrt{2}}-\frac{6}{\sqrt{8}-\sqrt{12}}\right] = ?$

$\sqrt{33124} \times \sqrt{2601} - (83)^{2} = (?)^{2} + (37)^{2}$