sqrt{33124} times sqrt{2601} - (83)^{2} = (?) | vedclass

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Question

(D) First,calculate the square roots: $\sqrt{33124} = 182$ and $\sqrt{2601} = 51$.Next,calculate the squares: $(83)^{2} = 6889$ and $(37)^{2} = 1369$.

Vedclass · Accepted Answer

$32$

Vedclass · Answer

(D) First,calculate the square roots: $\sqrt{33124} = 182$ and $\sqrt{2601} = 51$.Next,calculate the squares: $(83)^{2} = 6889$ and $(37)^{2} = 1369$.Substitute these values into the equation: $(182 	imes 51) - 6889 = (?)^{2} + 1369$.Calculate the product: $182 	imes 51 = 9282$.Now,the equation becomes: $9282 - 6889 = (?)^{2} + 1369$.Simplify the left side: $2393 = (?)^{2} + 1369$.Subtract $1369$ from both sides: $(?)^{2} = 2393 - 1369 = 1024$.Finally,find the square root: $? = \sqrt{1024} = 32$.

$\sqrt{33124} \times \sqrt{2601} - (83)^{2} = (?)^{2} + (37)^{2}$

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