left(frac{sqrt{625}}{11} times frac{14}{sqrt{ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) First,evaluate the square roots in the expression:$\sqrt{625} = 25$$\sqrt{25} = 5$$\sqrt{196} = 14$Substitute these values into the expression:$\l

Vedclass · Accepted Answer

$5$

Vedclass · Answer

(A) First,evaluate the square roots in the expression:$\sqrt{625} = 25$$\sqrt{25} = 5$$\sqrt{196} = 14$Substitute these values into the expression:$\left(\frac{25}{11} 	imes \frac{14}{5} 	imes \frac{11}{14}ight)$Now,cancel the common terms in the numerator and denominator:$= \left(\frac{25}{5} 	imes \frac{14}{14} 	imes \frac{11}{11}ight)$$= 5 	imes 1 	imes 1 = 5$

$\left(\frac{\sqrt{625}}{11} \times \frac{14}{\sqrt{25}} \times \frac{11}{\sqrt{196}}\right)$ is equal to

Similar Questions

Three-fifth of the square of a certain number is $126.15$. What is the number?

The largest among the numbers $\sqrt{7}-\sqrt{5}$,$\sqrt{5}-\sqrt{3}$,$\sqrt{9}-\sqrt{7}$,and $\sqrt{11}-\sqrt{9}$ is:

$\sqrt{\frac{48.4}{0.289}}$ is equal to

The square root of $\frac{(0.75)^{3}}{1-0.75} + [0.75 + 0.75^{2} + 1]$ is

If $\sqrt{\left(1+\frac{27}{169}\right)}=1+\frac{x}{13},$ then $x$ equals

Vedclass Test Series

Exam Paper Generator

Online Exam Module