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(C) Given equations are:$4x - 19y + 13 = 0$ ... $(i)$$13x - 23y + 19 = 0$ ... $(ii)$Using the cross-multiplication method for $a_1x + b_1y + c_1 = 0$

Vedclass · Accepted Answer

$(-2/5, 3/5)$

Vedclass · Answer

(C) Given equations are:$4x - 19y + 13 = 0$ ... $(i)$$13x - 23y + 19 = 0$ ... $(ii)$Using the cross-multiplication method for $a_1x + b_1y + c_1 = 0$ and $a_2x + b_2y + c_2 = 0$:$\frac{x}{b_1c_2 - b_2c_1} = \frac{y}{c_1a_2 - c_2a_1} = \frac{1}{a_1b_2 - a_2b_1}$Here,$a_1 = 4, b_1 = -19, c_1 = 13$ and $a_2 = 13, b_2 = -23, c_2 = 19$.$\frac{x}{(-19)(19) - (-23)(13)} = \frac{y}{(13)(13) - (19)(4)} = \frac{1}{(4)(-23) - (13)(-19)}$$\frac{x}{-361 + 299} = \frac{y}{169 - 76} = \frac{1}{-92 + 247}$$\frac{x}{-62} = \frac{y}{93} = \frac{1}{155}$$x = -62 / 155 = -2 / 5$$y = 93 / 155 = 3 / 5$Thus,the solution is $(-2/5, 3/5)$.

Solve the following pairs of equations by the cross-multiplication method:
$4x - 19y + 13 = 0$
$13x - 23y + 19 = 0$

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Solve the following pairs of equations by the cross-multiplication method:$4x - 19y + 13 = 0$$13x - 23y + 19 = 0$