The total weight of a father and his son is 7 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Let the weight of the father be $x \, kg$ and the weight of the son be $y \, kg$.According to the problem,the total weight is $x + y = 70$ (Equati

Vedclass · Accepted Answer

Father: $60 \, kg$,Son: $10 \, kg$

Vedclass · Answer

(A) Let the weight of the father be $x \, kg$ and the weight of the son be $y \, kg$.According to the problem,the total weight is $x + y = 70$ (Equation $1$).The weight of the son is one-sixth of the father's weight,so $y = \frac{1}{6}x$,which implies $x = 6y$ or $x - 6y = 0$ (Equation $2$).Substitute $x = 6y$ into Equation $1$:$6y + y = 70$$7y = 70$$y = 10 \, kg$.Now,substitute $y = 10$ into $x = 6y$:$x = 6 	imes 10 = 60 \, kg$.Therefore,the father's weight is $60 \, kg$ and the son's weight is $10 \, kg$.

The total weight of a father and his son is $70 \, kg$. The weight of the son is one-sixth of the weight of his father. Find the weight of the father and the son.

Similar Questions

$A$ two-digit number is obtained by either multiplying the sum of the digits by $8$ and then subtracting $5$,or by multiplying the difference of the digits by $16$ and then adding $3$. Find the number.

After $x$ years,the sum of the ages of Sachin and Sehwag will be $y$ years,then the sum of the ages before $3$ years was $\ldots \ldots \ldots \ldots$ years.

Solve the following pairs of equations by cross-multiplication method:
$3x - 4y = 17$
$4x - 5y = 21$

Subtraction of two numbers is $5$. If the larger number is $x$,then the smaller number is $y = \ldots \ldots \ldots \ldots$

$x=-1$ and $y=-2$ is one of the solutions of the equation $\ldots \ldots \ldots \ldots$

Vedclass Test Series

Exam Paper Generator

Online Exam Module