Solutions A,B,C and D are respectively 0.1 M | vedclass

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(A) Isotonic solutions have the same molar concentration of solute particles in the solution.We calculate the molar concentration of particles (van't

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$A$ and $B$

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(A) Isotonic solutions have the same molar concentration of solute particles in the solution.We calculate the molar concentration of particles (van't Hoff factor $i 	imes M$):For $A$ (glucose): $1 	imes 0.1 \ M = 0.1 \ M$.For $B$ $(NaCl)$: $2 	imes 0.05 \ M = 0.1 \ M$.For $C$ $(BaCl_{2})$: $3 	imes 0.05 \ M = 0.15 \ M$.For $D$ $(AlCl_{3})$: $4 	imes 0.1 \ M = 0.4 \ M$.Since solutions $A$ and $B$ have the same concentration of particles $(0.1 \ M)$,they are isotonic.

Solutions $A$,$B$,$C$ and $D$ are respectively $0.1 \ M$ glucose,$0.05 \ M \ NaCl$,$0.05 \ M \ BaCl_{2}$ and $0.1 \ M \ AlCl_{3}$. Which one of the following pairs is isotonic?

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