The correct order of boiling point of the giv | vedclass

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(B) The elevation in boiling point is a colligative property,which is directly proportional to the van't Hoff factor $(i)$ for solutions of the same n

Vedclass · Accepted Answer

$1 \ N \ KNO_3 = 1 \ N \ NaCl > 1 \ N \ CH_3COOH > 1 \ N \ 	ext{sucrose}$

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(B) The elevation in boiling point is a colligative property,which is directly proportional to the van't Hoff factor $(i)$ for solutions of the same normality $(N)$.$KNO_3$ and $NaCl$ are strong electrolytes,so they dissociate completely into $2$ ions each $(i = 2)$.$CH_3COOH$ is a weak electrolyte and dissociates partially,so its $i$ value is between $1$ and $2$ $(1 Sucrose is a non-electrolyte,so it does not dissociate $(i = 1)$.Since $i$ values are $KNO_3 = 2$,$NaCl = 2$,$CH_3COOH \approx 1.05$ (partial dissociation),and $	ext{sucrose} = 1$,the order of boiling point is $1 \ N \ KNO_3 = 1 \ N \ NaCl > 1 \ N \ CH_3COOH > 1 \ N \ 	ext{sucrose}$.

The correct order of boiling point of the given aqueous solutions is:

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