Simplify the following:sqrt{45}-3 sqrt{20}+4 | vedclass

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(C) To simplify the expression $\sqrt{45}-3 \sqrt{20}+4 \sqrt{5}$,we first factor the numbers inside the square roots:$\sqrt{45} = \sqrt{9 	imes 5} =

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$\sqrt{5}$

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(C) To simplify the expression $\sqrt{45}-3 \sqrt{20}+4 \sqrt{5}$,we first factor the numbers inside the square roots:$\sqrt{45} = \sqrt{9 	imes 5} = 3 \sqrt{5}$$\sqrt{20} = \sqrt{4 	imes 5} = 2 \sqrt{5}$Now,substitute these values back into the expression:$3 \sqrt{5} - 3(2 \sqrt{5}) + 4 \sqrt{5}$$= 3 \sqrt{5} - 6 \sqrt{5} + 4 \sqrt{5}$$= (3 - 6 + 4) \sqrt{5}$$= 1 \sqrt{5} = \sqrt{5}$

Simplify the following:
$\sqrt{45}-3 \sqrt{20}+4 \sqrt{5}$

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Simplify the following:$\sqrt{45}-3 \sqrt{20}+4 \sqrt{5}$