Similar charges are placed at corners of a square and a charge $q_0$ is placed at it's centre find net force on it
Similar charges are placed at corners of a square and a charge $q_0$ is placed at it's centre find net force on it
- A
$2\sqrt 2 \frac{{kq{q_0}}}{{{r^2}}}$
- B
$\sqrt 2 \frac{{kq{q_0}}}{{{r^2}}}$
- C
$\frac{{2kq{q_0}}}{{{r^2}}}$
- D
$\frac{1}{{2\sqrt 2 }}\frac{{kq{q_0}}}{{{r^2}}}$
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Three charge $q$, $Q$ and $4q$ are placed in a straight line of length $l$ at points distant $0,\,\frac {l}{2}$ and $l$ respectively from one end. In order to make the net froce on $q$ zero, the charge $Q$ must be equal to
Three charge $q$, $Q$ and $4q$ are placed in a straight line of length $l$ at points distant $0,\,\frac {l}{2}$ and $l$ respectively from one end. In order to make the net froce on $q$ zero, the charge $Q$ must be equal to
Select the correct alternative
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As shown in the figure. a configuration of two equal point charges $\left( q _0=+2 \mu C \right)$ is placed on an inclined plane. Mass of each point charge is $20\,g$. Assume that there is no friction between charge and plane. For the system of two point charges to be in equilibrium (at rest) the height $h = x \times 10^{-3}\,m$ The value of $x$ is $..........$.(Take $\left.\frac{1}{4 \pi \varepsilon_0}=9 \times 10^9\,Nm ^2 C ^{-2}, g=10\,ms ^{-1}\right)$
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- [JEE MAIN 2023]
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Assertion : A deuteron and an $\alpha -$ particle are placed in an electric field. If $F_1$ and $F_2$ be the forces acting on them and $a_1$ and $a_2$ be their accelerations respectively then, $a_1 = a_2$.
Reason : Forces will be same in electric field
Assertion : A deuteron and an $\alpha -$ particle are placed in an electric field. If $F_1$ and $F_2$ be the forces acting on them and $a_1$ and $a_2$ be their accelerations respectively then, $a_1 = a_2$.
Reason : Forces will be same in electric field
- [AIIMS 2015]