Show that $0 . \overline{076923}=\frac{1}{13}$
Visualise $-4.126$ on the number line, using successive magnification.
If $x=5+2 \sqrt{6},$ then find the value of $x^{2}+\frac{1}{x^{2}}$ and $x^{3}+\frac{1}{x^{3}}$
Find the value
$625^{\frac{3}{4}}$
Simplify: $\left[5\left(8^{\frac{1}{3}}+27^{\frac{1}{3}}\right)^{3}\right]^{\frac{1}{4}}$
Add $4 \sqrt{6}-8 \sqrt{10}$ and $3 \sqrt{6}+12 \sqrt{10}$