Show that $a_{1}, a_{2}, \ldots, a_{n}, \ldots$ form an $AP$ where $a_{n}$ is defined as $a_{n}=9-5n$. Find the sum of the first $15$ terms.

  • A
    $421$
  • B
    $486$
  • C
    $-465$
  • D
    $-476$

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