Two point masses $m$ and $M$ are separated by a distance $L$. The distance of the centre of mass of the system from m is
$L(m/M)$
$L(M/m)$
$L\left( {\frac{M}{{m + M}}} \right)$
$L\left( {\frac{m}{{m + M}}} \right)$
To find the centre of mass of rigid body why it is not possible to know$\sum {{m_i}\overrightarrow {{r_i}} } $ for all the particles ?
Two uniform plates of the same thickness and area but of different materials, one shaped like an isosceles triangle and the other shaped like a rectangle are joined together to form a composite body as shown in the figure alongside.If the centre of mass of the composite body is located at the mid-point of their common side, then the ratio between masses of the triangle to that of the rectangle is
Five masses are placed in a plane as shown in figure. The coordinates of the centre of mass are nearest to.
A $T$ shaped object with dimensions shown in the figure, is lying a smooth floor. A force $'\vec F'$ is applied at the point $P$ parallel to $AB,$ such that the object has only the translational motion without rotation. Find the location of $P$ with respect to $C$
Three point particles of masses $1.0\; \mathrm{kg} .1 .5 \;\mathrm{kg}$ and $2.5\; kg$ are placed at three comers of a right angle triangle of sides $4.0\; \mathrm{cm}, 3.0 \;\mathrm{cm}$ and $5.0\; \mathrm{cm}$ as shown in the figure. The center of mass of the system is at a point