Two point masses m and M are separated by a d | vedclass

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(C) Let the position of mass $m$ be at the origin $(x_1 = 0)$ and the position of mass $M$ be at $(x_2 = L)$ along the $x$-axis.The formula for the ce

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$L\left( \frac{M}{m + M} \right)$

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(C) Let the position of mass $m$ be at the origin $(x_1 = 0)$ and the position of mass $M$ be at $(x_2 = L)$ along the $x$-axis.The formula for the center of mass $X_{cm}$ of a two-particle system is given by:$X_{cm} = \frac{m_1x_1 + m_2x_2}{m_1 + m_2}$Substituting the values:$X_{cm} = \frac{m(0) + M(L)}{m + M}$$X_{cm} = \frac{ML}{m + M} = L\left( \frac{M}{m + M} \right)$Thus,the distance of the center of mass from $m$ is $L\left( \frac{M}{m + M} \right)$.

Two point masses $m$ and $M$ are separated by a distance $L$. The distance of the centre of mass of the system from $m$ is

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