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Question

(c)

Here, the coordinates of the centre of mass of the three rods are:

$\left(0, \frac{ L }{2}\right),\left(\frac{ L }{2}, 0\right),\left(\frac{

Vedclass · Accepted Answer

$\left(\frac{L}{3}, \frac{L}{2}\right)$

Vedclass · Answer

(c)

Here, the coordinates of the centre of mass of the three rods are:

$\left(0, \frac{ L }{2}\right),\left(\frac{ L }{2}, 0\right),\left(\frac{ L }{2}, L \right)$

The arrangement is symmetric about the line $y=\frac{L}{2}$

Hence the y coordinate of the centre of mass is $\frac{L}{2}$.

Now,$x$ coordinate of the centre of mass $=\frac{\sum m_i x_i}{\sum m_i}$

$=\frac{ L }{3}$

Therefore , the centre of mass of the arrangement is at $\left(\frac{ L }{3}, \frac{ L }{2}\right)$.

Locate the centre of mass of arrangement shown in figure. The three rods are identical in mass and length

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