Seven chits are numbered $1$ to $7$. Three are drawn one by one with replacement. The probability that the least number on any selected chit is $5$ is:
- A$1 - (\frac{2}{7})^3$
- B$4 \times (\frac{2}{7})^3$
- C$(\frac{3}{7})^3 - (\frac{2}{7})^3$
- D$(\frac{3}{7})^3$
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