Select the incorrect statement with regard to | vedclass

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Question

(a): Haemophilia is sex&shy;linked disease which is also known as bleeder&rsquo;s disease as the patient will continue to bleed even from a minor cut

Vedclass · Accepted Answer

It is a dominant disease.

Vedclass · Answer

(a): Haemophilia is sex&shy;linked disease which is also known as bleeder&rsquo;s disease as the patient will continue to bleed even from a minor cut since he or she does not possess the natural phenomenon of blood clotting due to absence of antihaemophiliac globulin or factor $VIII$ (haemophilia -$A$) and plasma thromboplastin factor $IX$ (haemophilia-$B$, Christmas disease) essential for it. As a result of continuous bleeding the patient may die of blood loss. It is geneticallydue to the presence ofa recessive sex linked gene $h$, carried by $X$-&shy;chromosome. A female becomes haemophiliac only when both of her $X$-&shy;chromosomes carry the gene $(X^hX^h)$. However, such females generally die before birth because the combination of these two recessive alleles is lethal. A female having only one allele for haemophilia $(XX^h)$ appears normal because the allele for normal blood clotting present on the other X&shy;chromosome is dominant. Such females are known as carriers. In case of males, a single gene for the defect is able to express itself as the $Y$&shy; chromosome is devoid of any corresponding allele $(X^hY)$.

Select the incorrect statement with regard to haemophilia.

Similar Questions

Describe pedigree analysis and draw its symbols.

The pedigree chart given below shows a particular trait which is absent in parents but present in the next generation irrespective of sexes. Draw your conclusion on the basis of the pedigree.

Given is : $X$ is the chromosome with gene for haemophilia and $X$ is the chromosome with normal gene. Which of the following individuals will act as carrier for haemophilia

Choose correct option.

$(i)$ The heterozygous female transmit the disease to son.

$(ii)$ Change in the shape of the $RBC$ from biconcave disc to elongated sickle like structure.

$(iii)$ Mentally retarded.

$(iv)$ Heamoglobin not formed proper amount in blood.

Haemolytic jaundice is caused due to a dominant gene but only $10\%$ of the people actually develop the disease. A heterozygous man marries a homozygous normal woman; what proportion of the children would be expected to develop the haemolytic disease