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(C) Color blindness is an $X$-linked recessive trait. Let $X^C$ be the allele for color blindness and $X$ be the allele for normal vision.$1$. The wom

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be either color-blind or have normal vision.

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(C) Color blindness is an $X$-linked recessive trait. Let $X^C$ be the allele for color blindness and $X$ be the allele for normal vision.$1$. The woman's father was color-blind $(X^CY)$,so she must have inherited the $X^C$ allele from him. Since she has normal vision,her genotype is $XX^C$.$2$. The man is color-blind,so his genotype is $X^CY$.$3$. The cross is $XX^C 	imes X^CY$.$4$. The possible genotypes for their children are: $XX^C$ (normal vision daughter),$X^CX^C$ (color-blind daughter),$XY$ (normal vision son),and $X^CY$ (color-blind son).$5$. For any son,there is a $50\%$ chance of being color-blind and a $50\%$ chance of having normal vision. Therefore,the fourth boy can be either color-blind or have normal vision.

$A$ woman with normal vision,but whose father was color-blind,marries a color-blind man. Suppose their fourth child is a boy. This boy will be ....... .

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