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(NONE) In option $A$,the two complexes are $[Co(NO_2)(H_2O)(en)_2]Cl_2$ and $[CoCl(NO_2)(en)_2]Cl \cdot H_2O$. These are hydrate isomers because the n

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$[Cr(NO_2)(NH_3)_5][ZnCl_4] , [Cr(ONO)(NH_3)_5][ZnCl_4] \longrightarrow$ Linkage isomerism

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(NONE) In option $A$,the two complexes are $[Co(NO_2)(H_2O)(en)_2]Cl_2$ and $[CoCl(NO_2)(en)_2]Cl \cdot H_2O$. These are hydrate isomers because the number of water molecules inside and outside the coordination sphere differs.In option $B$,the two complexes are $[Cu(NH_3)_4][PtCl_4]$ and $[CuCl(NH_3)_3][PtCl_3(NH_3)]$. These are coordination isomers as the ligands are exchanged between the cationic and anionic parts.In option $C$,the two complexes are $[Ni(CN)(H_2O)(NH_3)_4]Cl$ and $[NiCl(H_2O)(NH_3)_4]CN$. These are ionisation isomers because the counter ions ($Cl^-$ and $CN^-$) are exchanged with ligands inside the coordination sphere.In option $D$,the complexes are $[Cr(NO_2)(NH_3)_5][ZnCl_4]$ and $[Cr(ONO)(NH_3)_5][ZnCl_4]$. These are linkage isomers because the ambidentate ligand $NO_2^-$ is bonded through different donor atoms ($N$ vs $O$).Wait,re-evaluating option $A$: The formula $[Co(NO_2)(H_2O)(en)_2]Cl_2$ and $[CoCl(NO_2)(en)_2]Cl \cdot H_2O$ are indeed hydrate isomers. However,looking closely at the coordination sphere,the first complex has $Cl_2$ outside,while the second has $Cl$ outside and $H_2O$ outside. This is a valid example of hydrate isomerism.Actually,all options provided are technically correct examples of their respective isomerism types. However,in many textbooks,option $A$ is often cited as a classic example of hydrate isomerism. Upon closer inspection,all matches are correct. If forced to choose an error,there is no incorrect match provided in the list.

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