The spin-only magnetic moment of a divalent i | vedclass

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(A) The atomic number of the element is $Z = 29$,which corresponds to Copper $(Cu)$.The electronic configuration of $Cu$ is $[Ar] 3d^{10} 4s^1$.For th

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$2$

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(A) The atomic number of the element is $Z = 29$,which corresponds to Copper $(Cu)$.The electronic configuration of $Cu$ is $[Ar] 3d^{10} 4s^1$.For the divalent ion $Cu^{2+}$,the electronic configuration is $[Ar] 3d^9$.In the $3d$ orbital,there are $9$ electrons,which means there is $1$ unpaired electron.The spin-only magnetic moment formula is $\mu = \sqrt{n(n+2)} \ BM$,where $n$ is the number of unpaired electrons.Substituting $n = 1$: $\mu = \sqrt{1(1+2)} = \sqrt{3} \approx 1.73 \ BM$.Rounding $1.73$ to the nearest integer gives $2 \ BM$.

List-$I$ (Complex)	List-$II$ (Spin only Magnetic moment)
$A$. $[CoF_6]^{3-}$	$I$. $0$
$B$. $[Co(C_2O_4)_3]^{3-}$	$II$. $\sqrt{24}$
$C$. $[FeF_6]^{3-}$	$III$. $\sqrt{8}$
$D$. $[Mn(CN)_6]^{3-}$	$IV$. $\sqrt{35}$
	$V$. $\sqrt{15}$

The spin-only magnetic moment of a divalent ion in aqueous solution (atomic number $29$) is ...... $BM.$

Similar Questions

Which of the following complexes possesses a meridional $(mer)$ isomer?

Select the incorrect match.

Total number of relatively more stable isomer$(s)$ possible for octahedral complex $[Cu(en)_2(SCN)_2]$ will be $.........$

Match the following:

List-$I$ (Complex) List-$II$ (Spin only Magnetic moment)

$A$. $[CoF_6]^{3-}$ $I$. $0$

$B$. $[Co(C_2O_4)_3]^{3-}$ $II$. $\sqrt{24}$

$C$. $[FeF_6]^{3-}$ $III$. $\sqrt{8}$

$D$. $[Mn(CN)_6]^{3-}$ $IV$. $\sqrt{35}$

$V$. $\sqrt{15}$

Among $TiF_6^{2-}$,$CoF_6^{3-}$,$Cu_2Cl_2$ and $NiCl_4^{2-}$,the colourless species are:

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