Select the correct statement

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Question

$\left(\Delta \mathrm{S}_{\mathrm{r}}\right)_{\mathrm{T}_{2}}-\left(\Delta \mathrm{S}_{\mathrm{r}}\right)_{\mathrm{T}_{1}}=\left(\Delta \mathrm{C}_{\m

Vedclass · Accepted Answer

Rate constant of all the elementry reaction increases with increase in temperature

Vedclass · Answer

$\left(\Delta \mathrm{S}_{\mathrm{r}}\right)_{\mathrm{T}_{2}}-\left(\Delta \mathrm{S}_{\mathrm{r}}\right)_{\mathrm{T}_{1}}=\left(\Delta \mathrm{C}_{\mathrm{p}}\right)_{\mathrm{r}} \ln \frac{\mathrm{T}_{2}}{\mathrm{T}_{1}}$

$(A)$ It depends on $\left(\Delta \mathrm{C}_{\mathrm{p}}\right)_{\mathrm{r}}$

$(B)$ It depends on $\left(\Delta \mathrm{C}_{\mathrm{p}}\right)_{\mathrm{r}}$

$(C)$ $\mathrm{k}=4 \mathrm{e}^{-\mathrm{E} \mathrm{a} / \mathrm{RT}}$

$(D)$ Activation energy is independent of

temperature

$p ( mm Hg )$	$50$	$100$	$200$	$400$
Relative $t _{1 / 2}( s )$	$4$	$2$	$1$	$0.5$

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