For a given reaction $t_{1/2} = \frac{1}{k.a}$ the order of reaction will be
$0$
$1$
$2$
$3$
The rate of certain reaction depends on concentration according to the equation $\frac{{ - dc}}{{dt}}\, = \,\frac{{{K_1}C}}{{1 + {K_2}C}},$ what is the order, when concentration $(c)$ is very-very high
The rate of disappearance of $S{O_2}$ in the reaction $2S{O_2} + {O_2} \to 2S{O_3}$ is $1.28 \times {10^{ - 3}}g/sec$ then the rate of formation of $S{O_3}$ is
Reaction : $KCl{O_3} + 6FeS{O_4} + 3{H_2}S{O_4} \to $ $KCl + 3F{e_2}{\left( {S{O_4}} \right)_3} + 3{H_2}O$
Which is True $(T)$ and False $(F) $ in the following sentence ?
The reaction is complex.
For a reaction $2A + B \to $ Products, doubling the initial concentration of both the reactants increases the rate by a factor of $8$, and doubling the concentration of $+B$ alone doubles the rate. The rate law for the reaction is
The following results have been obtained during the kinetic studies of the reaction:
$2 A+B \rightarrow C+D$
Experiment | $[ A ] / mol L ^{-1}$ | $[ B ] / mol L ^{-1}$ | Initial rate of formation of $D / mol \,L ^{-1} \,min ^{-1}$ |
$I$ | $0.1$ | $0.1$ | $6.0 \times 10^{-3}$ |
$II$ | $0.3$ | $0.2$ | $7.2 \times 10^{-2}$ |
$III$ | $0.3$ | $0.4$ | $2.88 \times 10^{-1}$ |
$IV$ | $0.4$ | $0.1$ | $2.40 \times 10^{-2}$ |
Determine the rate law and the rate constant for the reaction.