Resistance of a piece of rubber is more than that of a piece of copper.

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Similar Questions

Study the following circuit and answer the following questions

$(i)$ State the type of combination of the two resistors in the circuit.

$(ii)$ How much current would flow through

$(a)$ $10\, \Omega$ resistor and

$(b)$ $15\, \Omega$ resistors ?

$(iii)$ What would be the ammeter reading ?

How are ammeters and voltmeters connected in a circuit ? What do they help us measure ?

Two wires of the same metal have the same length, but cross$-$sections are in the ratio $3: 1 .$ They are joined in series. The resistance of the thicker wire is $10\, ohm.$ The total resistance of the combination will be

$B_{1}, B_{2}$ and $B_{3}$ are three identical bulbs connected as shown in the figure. When all the three bulbs glow, a current of $3 \,A$ is recorded by the ammeter $A$.

$(i)$ What happens to the glow of the other two bulbs when the bulb $B_{1}$ gets fused?

$(ii)$ What happens to the reading of $A_{1}, A_{2}, A_{3}$ and A when the bulb $B_{2}$ gets fused ?

A potential difference $V$ is applied across a conductor of length $L$ and diameter $D .$ How is the resistance $R$ of the conductor affected, when in turn $(i)$ $V$ is halved $(ii)$ $L$ is halved and $(iii)$ $D$ is doubled ? Justify your answer in each case.