Two wires of the same metal have the same length, but cross$-$sections are in the ratio $3: 1 .$ They are joined in series. The resistance of the thicker wire is $10\, ohm.$ The total resistance of the combination will be

  • A

    $40 / 3\, ohm$

  • B

    $5 / 2\,ohm$

  • C

    $100\, ohm$

  • D

    $40\, ohm$

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