Two wires of the same metal have the same length, but cross-sections are in the ratio $3 : 1$. They are joined in series. The resistance of the thicker wire is $10\, \Omega$. The total resistance of the combination will be:

  • A
    $40/3\, \Omega$
  • B
    $5/2\, \Omega$
  • C
    $100\, \Omega$
  • D
    $40\, \Omega$

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