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(B) According to Ohm's law,the resistance $R$ is given by $R = \frac{V}{I}$.For a quotient,the relative error is the sum of the relative errors of the

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$6$

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(B) According to Ohm's law,the resistance $R$ is given by $R = \frac{V}{I}$.For a quotient,the relative error is the sum of the relative errors of the individual quantities: $\frac{\Delta R}{R} = \frac{\Delta V}{V} + \frac{\Delta I}{I}$.To find the percentage error,we multiply by $100$:$\frac{\Delta R}{R} 	imes 100 = \left( \frac{\Delta V}{V} 	imes 100 ight) + \left( \frac{\Delta I}{I} 	imes 100 ight)$.Given that the percentage error in voltage $\frac{\Delta V}{V} 	imes 100 = 3\%$ and the percentage error in current $\frac{\Delta I}{I} 	imes 100 = 3\%$.Therefore,the percentage error in resistance is $3\% + 3\% = 6\%$.

Resistance of a given wire is obtained by measuring the current flowing in it and the voltage difference applied across it. If the percentage errors in the measurement of the current and the voltage difference are $3\%$ each,then the error in the value of resistance of the wire is ........ $\%$

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