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Question

(c)

Consider the given diagram,

Assuming area observed and screen both circular, we have

$	heta_1=	heta_2 \Rightarrow \frac{d_1}{f}=\frac{d

Vedclass · Accepted Answer

$10^{12}$

Vedclass · Answer

(c)

Consider the given diagram,

Assuming area observed and screen both circular, we have

$	heta_1=	heta_2 \Rightarrow \frac{d_1}{f}=\frac{d_2}{h} \Rightarrow \frac{d_2}{d_1}=\frac{h}{f}$

where, $d_1=$ diameter of camera screen and $d_2=$ diameter of area on earth.

Now, $\frac{area \,observed \,on \,earth}{area \,of \,screen}=\frac{A_0}{A}$

$=\frac{\left(\frac{\pi \cdot d_2^2}{4}ight)}{\left(\frac{\pi \cdot d_1^2}{4}ight)}=\frac{d_2^2}{d_1^2}$

$\Rightarrow \quad \frac{A_0}{A}=\left(\frac{h}{f_1}ight)^2=\left(\frac{500 	imes 10^{+3}}{50 	imes 10^{-2}}ight)^2$

$=\left(10 	imes 10^3 	imes 10^2ight)^2=\left(10^6ight)^2=10^{12}$

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